Loops + Updating variables

I'm trying to do some iterative calculations by repeatedly calling a function 'calculate_box' which returns a column array of values on each iteration. I calculate the first column array outside of any loops, and store the value of the first item (i.e. (1,1) ).

I then start my loop on the 2nd calculation. From the 2nd calculation onwards, I would like my code to compare the first value in the array ( so (1,2) ) with the previous iteration.

If the value is the same, I would like the value to be discarded, and 'shifty' - an input to the function to be increased by one, and the calculation run again and shifty increased, until such a time as the value returned is different to the previous one.

When this occurs, I would like the value to be stored, 'shifty' to be set to this value plus min_dist, then the process to return to the start of the main loop.

My code is below, I'd be very grateful if anyone could explain my error/how to resolve it. Many thanks in advance!

n_eig = 5;
range = [0,50];
min_dist = 1; %min distance between eigenvalues
Initial_matrix = B; 
gcompute = [0.1,0.1,0.1,0.1,0.1]; %initial guess 
resultz = zeros(n_eig,n_eig); 
resultz(:,1) = calculate_box(P,gcompute,100000,range(1)); 
shifty = resultz(1,1) + min_dist;
for j = 2:1:n_eig    
    resultz(:,j) = calculate_box(P,gcompute,100000,shifty); 
    while resultz(1,j) == resultz(1,j-1)    
        shifty = shifty + min_dist;    
        resultz(:,j) = calculate_box(P,gcompute,100000,shifty);    
    end    
    shifty = resultz(1,j) + min_dist;                 
end

[Daksh]

Hi, can you share the calculate_box function and other data variables so it is possible to reproduce this issue on my side? Only then I shall be able to debug and resolve the error you're experiencing. Thanks!

[Jan]

Before we can explain the cause of the error, you have to mention, what you consider as error. You have explained the intention of the code and show a certain part of it. We cannot run it, so there is no chance to guess, what the problem is.