Use of brackets while multiplying expression

4 Ansichten (letzte 30 Tage)
BALPARTAP SINGH
BALPARTAP SINGH am 11 Feb. 2021
Kommentiert: Stephen23 am 11 Feb. 2021
E_d=2.6*(((1-alpha)/Ku)^ 1/3)*(Pe^(-2/3));
While using this expression answers comes out be -0.0065 but if 1/3 is taken in bracket the answer changes and result is shown in complex form. Please explain the backend calculation by MATLAB.
  2 Kommentare
Alan Stevens
Alan Stevens am 11 Feb. 2021
What are the values of the constants in the expression?
BALPARTAP SINGH
BALPARTAP SINGH am 11 Feb. 2021
alpha = 0.1198
Ku = -0.173016419
Pe = 17808.22486

Melden Sie sich an, um zu kommentieren.

Melden Sie sich an, um diese Frage zu beantworten.

Antworten (1)

Alan Stevens
Alan Stevens am 11 Feb. 2021
You have
E_d = 2.6*((1-alpha)/Ku)^1/3*Pe^(-2/3)
which only raises the bracketed term to the power 1, then divides the result by 3.
If you had
E_d = 2.6*((1-alpha)/Ku)^(1/3)*Pe^(-2/3)
you would be raising the bracketed term to the power 1/3, which would result in a complex number (because of the negative value of Ku).

Kategorien

Mehr zu Language Fundamentals finden Sie in Help Center und File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by