pick elements from a 3d array, based on an indexing matrix

11 Ansichten (letzte 30 Tage)
Bernhard
Bernhard am 26 Jan. 2021
Kommentiert: Stephen23 am 27 Jan. 2021
I have a 3d array A with nr rows, nc columns, and np pages, and an nr x nc indexing matrix I with integer elements between 1 and np. I want to create a matrix B with elements picked from A, where for each position (r,c) the element is picked from the page of A given by the value of I at that position.
A straightforward way to do this would be the double loop:
B = zeros(nr,nc);
for r = 1:nr
for c = 1:nc
p = I(r,c);
B(r,c) = A(r,c,p);
end
end
Is there a way to accelerate this by vectorization for large arrays?

Akzeptierte Antwort

Stephen23
Stephen23 am 26 Jan. 2021
Bearbeitet: Stephen23 am 26 Jan. 2021
% fake data:
nr = 5;
nc = 7;
np = 3;
A = randi(9,nr,nc,np);
I = randi(np,nr,nc)
I = 5×7
1 1 2 1 2 2 3 1 3 3 2 3 3 1 1 2 3 2 3 1 1 2 2 2 1 3 2 2 1 1 2 3 3 1 1
% your looped approach:
B = zeros(nr,nc);
for r = 1:nr
for c = 1:nc
p = I(r,c);
B(r,c) = A(r,c,p);
end
end
B
B = 5×7
7 1 6 2 3 7 6 6 4 3 1 5 5 4 4 1 3 2 2 2 6 4 3 8 2 1 7 9 9 9 6 2 5 1 6
% SUB2IND approach:
[xr,xc] = ndgrid(1:nr,1:nc);
X = sub2ind(size(A),xr,xc,I);
C = A(X)
C = 5×7
7 1 6 2 3 7 6 6 4 3 1 5 5 4 4 1 3 2 2 2 6 4 3 8 2 1 7 9 9 9 6 2 5 1 6
  2 Kommentare
Bernhard
Bernhard am 26 Jan. 2021
Thank you, Stephen, that is a nice gimmick. It took about 60% of the time needed for the looped approach.
Bernhard
Stephen23
Stephen23 am 27 Jan. 2021
@Bernhard: if the speed of this operation is very critical to your algorithm, then take a look inside the sub2ind file. The sub2ind function is generic, for any number of dimensions, but with a little effort you can write your own version that is hardcoded for the number of dimensions of your data and that does not require ndgrid beforehand. Whether it is worth the effort depends on your situation.

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Mehr zu Matrices and Arrays finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by