How to sort one array based on the order of a second array?

1 Ansicht (letzte 30 Tage)
David Mabwa
David Mabwa am 22 Jan. 2021
Kommentiert: David Mabwa am 22 Jan. 2021
Hi,
This seems like a very simple problem, but I can't seem to get it to work with the answers already available.
I have 2 string arrays:
A=["1a","1b","1c","1d","1e","2a","2b","2c","2d","2e"];
B=["A1_2a","U1_1c","Z1_2d","I1_1e","T1_1a","F1_2b","O1_1d","P1_2c","J1_2e","S1_1b"];
Let's say A is a newly sorted array from a previously disordered array (e.g. Q=["1c","2a","1e","2d","1b","2c","2e","1a","2b","1d"];)
How do I sort B, based on how Q was sorted?
The goal is to produce the array below
C=["T1_1a","S1_1b","U1_1c","O1_1d","I1_1e","A1_2a","F1_2b","P1_2c","Z1_2d","J1_2e"];
Thanks in advance.

Akzeptierte Antwort

Stephen23
Stephen23 am 22 Jan. 2021
As far as I can tell, the order of Q is irrelevant.
A = ["1a","1b","1c","1d","1e","2a","2b","2c","2d","2e"]; % sorted
B = ["A1_2a","U1_1c","Z1_2d","I1_1e","T1_1a","F1_2b","O1_1d","P1_2c","J1_2e","S1_1b"];
[~,X] = ismember(A,extractAfter(B,'_'));
C = B(X)
C = 1×10 string array
"T1_1a" "S1_1b" "U1_1c" "O1_1d" "I1_1e" "A1_2a" "F1_2b" "P1_2c" "Z1_2d" "J1_2e"

Weitere Antworten (0)

Kategorien

Mehr zu Multidimensional Arrays finden Sie in Help Center und File Exchange

Produkte


Version

R2020b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by