use of msgbox in matlab
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hi,
I tried to use the msgbox function in matlab, which I found here:
I tried to take the formula to display at which i we are currrently with the code:
h = msgbox(i)
unfortunately it's not working at all. From VBA I know that it's just necessary to enter msgbox and the variable, but that doesn't work either
what do I need t change?
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  Image Analyst
      
      
 am 11 Apr. 2013
        
      Bearbeitet: Image Analyst
      
      
 am 11 Apr. 2013
  
      You need to pass it a string
for k = 1 : 10
  message = sprintf('k = %4d\n', k);
  uiwait(msgbox(message));
  % You can use fprintf() instead if you don't want to prompt the user.
  fprintf(message); % Goes to command window.
end
Or better yet, use questdlg() so the user can have an opportunity to break out of your 1000 iteration loop:
for k = 1 : 10
  message = sprintf('k = %4d\nContinue?', k);
  reply = questdlg(message, 'Continue', 'OK', 'Cancel', 'OK');
  if strcmpi(reply, 'Cancel')
    % User said Cancel, so exit.
    break;
  end
end
I used k as a loop variable because you're not supposed to use i or j - they're the imaginary variable.
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  per isakson
      
      
 am 11 Apr. 2013
        
      Bearbeitet: per isakson
      
      
 am 11 Apr. 2013
  
          >> h = msgbox('This is my message') 
    h =
        0.0012
    >>
works fine here. Message should be a string.
[Added:] To show the value of the numeric variable: i
     h = msgbox( num2str( i ) )
VB do things more automagically than Matlab. Here you need to do the conversion explicitely.
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