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use of msgbox in matlab

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Locks
Locks am 11 Apr. 2013
hi,
I tried to use the msgbox function in matlab, which I found here:
I tried to take the formula to display at which i we are currrently with the code:
h = msgbox(i)
unfortunately it's not working at all. From VBA I know that it's just necessary to enter msgbox and the variable, but that doesn't work either
what do I need t change?

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Image Analyst
Image Analyst am 11 Apr. 2013
Bearbeitet: Image Analyst am 11 Apr. 2013
You need to pass it a string
for k = 1 : 10
message = sprintf('k = %4d\n', k);
uiwait(msgbox(message));
% You can use fprintf() instead if you don't want to prompt the user.
fprintf(message); % Goes to command window.
end
Or better yet, use questdlg() so the user can have an opportunity to break out of your 1000 iteration loop:
for k = 1 : 10
message = sprintf('k = %4d\nContinue?', k);
reply = questdlg(message, 'Continue', 'OK', 'Cancel', 'OK');
if strcmpi(reply, 'Cancel')
% User said Cancel, so exit.
break;
end
end
I used k as a loop variable because you're not supposed to use i or j - they're the imaginary variable.
  1 Kommentar
Locks
Locks am 12 Apr. 2013
thanks, that helps!

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Weitere Antworten (2)

per isakson
per isakson am 11 Apr. 2013
Bearbeitet: per isakson am 11 Apr. 2013
>> h = msgbox('This is my message')
h =
0.0012
>>
works fine here. Message should be a string.
[Added:] To show the value of the numeric variable: i
h = msgbox( num2str( i ) )
VB do things more automagically than Matlab. Here you need to do the conversion explicitely.

Locks
Locks am 11 Apr. 2013
What do I need to do if I would like to see which value the i has, which runs form 1 to 1000?

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