use of msgbox in matlab

9 Ansichten (letzte 30 Tage)
Locks
Locks am 11 Apr. 2013
hi,
I tried to use the msgbox function in matlab, which I found here:
I tried to take the formula to display at which i we are currrently with the code:
h = msgbox(i)
unfortunately it's not working at all. From VBA I know that it's just necessary to enter msgbox and the variable, but that doesn't work either
what do I need t change?

Akzeptierte Antwort

Image Analyst
Image Analyst am 11 Apr. 2013
Bearbeitet: Image Analyst am 11 Apr. 2013
You need to pass it a string
for k = 1 : 10
message = sprintf('k = %4d\n', k);
uiwait(msgbox(message));
% You can use fprintf() instead if you don't want to prompt the user.
fprintf(message); % Goes to command window.
end
Or better yet, use questdlg() so the user can have an opportunity to break out of your 1000 iteration loop:
for k = 1 : 10
message = sprintf('k = %4d\nContinue?', k);
reply = questdlg(message, 'Continue', 'OK', 'Cancel', 'OK');
if strcmpi(reply, 'Cancel')
% User said Cancel, so exit.
break;
end
end
I used k as a loop variable because you're not supposed to use i or j - they're the imaginary variable.
  1 Kommentar
Locks
Locks am 12 Apr. 2013
thanks, that helps!

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (2)

per isakson
per isakson am 11 Apr. 2013
Bearbeitet: per isakson am 11 Apr. 2013
>> h = msgbox('This is my message')
h =
0.0012
>>
works fine here. Message should be a string.
[Added:] To show the value of the numeric variable: i
h = msgbox( num2str( i ) )
VB do things more automagically than Matlab. Here you need to do the conversion explicitely.

Locks
Locks am 11 Apr. 2013
What do I need to do if I would like to see which value the i has, which runs form 1 to 1000?

Kategorien

Mehr zu Scope Variables and Generate Names finden Sie in Help Center und File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by