How to count the number of times that values changes?
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Mia Dier
am 9 Jan. 2021
Kommentiert: Mario Malic
am 9 Jan. 2021
A=[1 1 1 2 1 3 3 1 1]' I want to get:
B=[NaN 0 0 1 2 3 3 4 4]'
The second and third values of B are 0 because A doesn't change value. Fourth value is 1 because A changes value. Fifth value is 2 because A changes value again. And so on...
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Mario Malic
am 9 Jan. 2021
Bearbeitet: Mario Malic
am 9 Jan. 2021
Hello,
This should do the trick.
B = [NaN; cumsum(diff(A) ~= 0)]';
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