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splitting a array at defined interval

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strunack
strunack am 9 Apr. 2013
I have a array c of 276 elements. I want to split it into 3 separate array. The number of elements in each of these three array is within the array c itself.
vind=c(find(c>=10)) %gives me
vind =
45 45 183
I have to split the array c into three arrays with number of elements as 45, 45 and 183 respectively excluding the position of these three numbers. Pls suggest how it can be done.
with thanks

Akzeptierte Antwort

Cedric
Cedric am 9 Apr. 2013
Bearbeitet: Cedric am 9 Apr. 2013
Alternatively:
loc = find(c >= 10) ;
vind = c(loc) ;
c(loc) = [] ;
out = mat2cell(c, 1, vind) ;
  1 Kommentar
strunack
strunack am 10 Apr. 2013
I accepted this answer, because its very logical, clean and simple way to split without any loop. I could do the same with loop but in a rather inefficient way than Azzi's answer. Thanks to him too.

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Weitere Antworten (1)

Azzi Abdelmalek
Azzi Abdelmalek am 9 Apr. 2013
ii=1;
for k=1:numel(vind)
jj=vind(k)
out{k}=c(ii:jj)
ii=jj+1;
end
  1 Kommentar
Jan
Jan am 9 Apr. 2013
Bearbeitet: Jan am 9 Apr. 2013
Please add some code for the pre-allocation also. Otherwise we have to answer corresponding question next week again. Thanks.
As far as I understand, the OP wants the part from ii to jj-1 only.

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