Filter löschen
Filter löschen

plotting an array of doubles

2 Ansichten (letzte 30 Tage)
ksew ksew
ksew ksew am 5 Apr. 2013
im trying to plot an array with length of (5001 x 101 double) and need to store then in another array. I am using the following code to do so however only 1 values is being stored what im doing wrong
% code
for n =1:1:5001
snr1 = rms(input(n))/ rms(out(n));
end
end

Antworten (3)

Azzi Abdelmalek
Azzi Abdelmalek am 5 Apr. 2013
  2 Kommentare
ksew ksew
ksew ksew am 5 Apr. 2013
Bearbeitet: Azzi Abdelmalek am 5 Apr. 2013
i did this still nothing works
for n =1:1:5001
snr1(i) = rms(input(n))/ rms(out(n));
end
Azzi Abdelmalek
Azzi Abdelmalek am 5 Apr. 2013
Bearbeitet: Azzi Abdelmalek am 5 Apr. 2013
In your case, the counter is n not i then use
snr1(n)

Melden Sie sich an, um zu kommentieren.


Carlos
Carlos am 5 Apr. 2013
He means that you should do
for n =1:1:5001
snr1(n) = rms(input(n))/ rms(out(n));
end

Jan
Jan am 5 Apr. 2013
The suggested methods might work partially only, and this means, that they fail. You want a "5001 x 101 double" array, such that I guess the right hand side replies an [1 x 101] vector. Then:
snr1 = zeros(5001, 101); % Pre-allocate for speed!!!
for n = 1:5001
snr1(n, :) = rms(input(n)) / rms(out(n));
end
Using "input" as name of a variable has the disadvantage, that it shadows the built-in function with the same name. Such shadowing causes unexpected troubles frequently.

Kategorien

Mehr zu Antennas, Microphones, and Sonar Transducers finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by