Easy Noob Indexing Question

1 Ansicht (letzte 30 Tage)
Richard Keniuk
Richard Keniuk am 19 Dez. 2020
Kommentiert: Richard Keniuk am 27 Dez. 2020
I'm sure this answer is looming in front of me but I am missing it somehow. I have an array
A = [0 0;1 -1; -1 1;1 -1; -1 1];
and
B = [2 -2; -2 2;2 -2; -2 2;2 -2; -2 2;2 -2;0 0];
and I'm concatenating these two in the vertical direction but I only want rows 4:7 of my concatenated output.
I am doing this in two steps.
C = cat(1,A,B); % or some other calculation of vectors A and B
C = C(4:7,:);
How can I reduce this to one command by directly indexing the equation of "cat(1,A,B)" directly into C?
I know that I could do this by C = cat(1,A(end-1:end,:),B(1:2,:)). A and B are of variable length and I only want C to hold the concatenation +/-2 indices vertically. Is there another way in a single line?
  2 Kommentare
KALYAN ACHARJYA
KALYAN ACHARJYA am 19 Dez. 2020
Is there any issue with that, simplest and easiest?
C=[A;B];
C=C(4:7,:)
Image Analyst
Image Analyst am 19 Dez. 2020
My programs have thousands of lines of code. Why does yours have to be just one line of code instead of 2? Your last way of using end will work for variable sizes arrays.

Melden Sie sich an, um zu kommentieren.

Akzeptierte Antwort

Rishabh Mishra
Rishabh Mishra am 23 Dez. 2020
Hi,
Use the code below for resolving your issue:
C=[A;B];
C=C(4:7,:);
This is the simplest way to code the solution for the issue you are facing.
Hope this helps !
  1 Kommentar
Richard Keniuk
Richard Keniuk am 27 Dez. 2020
I guess I already had this to the "cleanest" implementation. I thought maybe I was missing something here.
Thanks for your help.

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Mehr zu Matrix Indexing finden Sie in Help Center und File Exchange

Tags

Produkte

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by