Implement double summation in Matlab
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Hi.
Could you help me implement these two equations in Matlab utilizing for loops?
SF is a matrix of 1400 rows and 120 columns.
N=120
t=1:1400
I think the first equation can be implemented with cumsum(SF,2) but I'm curious as to how it'd be with foor loops.


Thanks
Antworten (2)
The sigma symbol contains all syntactic elements that you need for a for loop:
y=0;%initialize to 0
for j=1:N
for i=1:j
y=y+f(i);
end
end
4 Kommentare
Jean Pazos
am 14 Dez. 2020
Bearbeitet: Jean Pazos
am 14 Dez. 2020
Rik
am 14 Dez. 2020
Yes, that was a typo, which I now corrected.
The point is that a sigma is easy to convert to a for-loop. If you function of i (f) is actually also a function of t, you should include that as well, but only if your output is no longer a function of t.
It doesn't look like a heap of for-loops is your optimal strategy. Do you actually want to use this for something? I would strongly suggest using the sum function and cumsum. That will be much faster, as Matlab can optimize a lot of the calculations.
Jean Pazos
am 14 Dez. 2020
Maybe cumprod is what you're looking for there? If you think about what should happen mathematically, that operator mean to take the product of all elements, right? That would make it analogous to the sigma operator, which uses + on all operators. Note that while 0 is the null operand for sum (or is it called unit operand?), for a product that operand is 1.
aisha chauhan
am 27 Mai 2023
Bearbeitet: Image Analyst
am 27 Mai 2023
0 Stimmen
Please convert this equation into MATLAB code:

1 Kommentar
Image Analyst
am 27 Mai 2023
Try a nested for loop:
theSum = 0;
for ii = 1 : Ncl
for ell = 1 : Nray
aHt = at(phi(ii, ell)^t, theta(ii, ell)^t)
theSum = theSum + alpha(ii, ell) * ar(phi(ii, ell)^r, theta(ii, ell)^r) * aHt^H
end
end
H = gamma * theSum;
But the equation seems weird, or maybe the nomenclature was just not explained. Like why are you raising a sub t to the H power when H is the result of the loop? To learn other fundamental concepts, invest 2 hours of your time here:
If you still have trouble, start your own question instead of posting in some 3 year old thread of @Jean Pazos's.
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