how to write special matrices

how can I write this matrix

                                           a=[0 0 0 0;
                                                0 0 0 1;
                                                0 0 1 0;
                                                0 0 1 1;
                                                0 1 0 0;
                                                0 1 0 1;
                                                0 1 1 0;
                                                0 1 1 1;
                                                1 0 0 0;
                                                1 0 0 1;
                                                1 0 1 0;
                                                1 0 1 1;
                                                1 1 0 0;
                                                1 1 0 1;
                                                1 1 1 0;
                                                1 1 1 1;]

using for loop?

[KALYAN ACHARJYA]

What you have tried so far?

dec2bin(1:15)

Using for loop, please share your efforts?

[safwan shraideh]

Ok Kalyan, but this is not matrix, this is char. Can you help me again?

Answer 1

[Bruno Luong]

>> dec2bin(0:2^4-1)-'0'

ans =

     0     0     0     0
     0     0     0     1
     0     0     1     0
     0     0     1     1
     0     1     0     0
     0     1     0     1
     0     1     1     0
     0     1     1     1
     1     0     0     0
     1     0     0     1
     1     0     1     0
     1     0     1     1
     1     1     0     0
     1     1     0     1
     1     1     1     0
     1     1     1     1

[safwan shraideh]

Thank you Bruno.

Answer 2

[Walter Roberson]

You can use the "odometer" code pattern.

https://www.mathworks.com/matlabcentral/answers/623358-get-a-combination-of-unique-paths-for-given-pair-of-numbers#comment_1082638

[safwan shraideh]

Thanks Walter.

Answer 3

[Setsuna Yuuki.]

I think it is not very efficient, but works

a = dec2bin(0:15);
i = 1;
while i<17
    c = randi([0 1],1,4);
    
    if(a(i,1:4) == sprintf('%g',c))
       b(i,1:4) = c;
       i = i+1;
    end
end

b =
     0     0     0     0
     0     0     0     1
     0     0     1     0
     0     0     1     1
     0     1     0     0
     0     1     0     1
     0     1     1     0
     0     1     1     1
     1     0     0     0
     1     0     0     1
     1     0     1     0
     1     0     1     1
     1     1     0     0
     1     1     0     1
     1     1     1     0
     1     1     1     1

[Stephen23]

Exactly as its author states, this is "not very efficient".

Or in one word, it is very inefficient. Best avoided.

[Setsuna Yuuki.]

I confirm, best avoided :D

[Bruno Luong]

I have impression Bastian wants to make us a joke.

[safwan shraideh]

It is not efficient, but thanks for your effort Bastian.