Filter löschen
Filter löschen

how to creating matrix h 4x2 with some rules

2 Ansichten (letzte 30 Tage)
Noru
Noru am 21 Mär. 2013
I have some trouble when creating matrix 4x2 with rules like below. the first column are integer and the other column are random number. I already create the syntax below.
for ii = 1:8,
nilai = mod(ii,2);
if nilai == 0
x(ii) = 0.95 + (1.05-0.95)*x(ii);
elseif nilai ~= 0
x(ii) = round(3 + (30-3)*x(ii));
elseif nilai ~= 0
x(ii) = 0.01 + (0.055-0.01)*x(ii);
else
x(ii) = 1.0 + (1.15-1.0)*x(ii);
end
end
x = reshape(x,4,2)';
but the result are
??? Error using ==> reshape
To RESHAPE the number of elements must not change.
anyone can help me with this problem..? any solutions are very welcome..
thank you.

Akzeptierte Antwort

the cyclist
the cyclist am 21 Mär. 2013
What is the shape of x before you start? It seems that it is probably not an 8-element array, so the reshape fails.
  3 Kommentare
the cyclist
the cyclist am 21 Mär. 2013
You did not answer my question. What is the shape of x BEFORE this loop?
As you can see from Image Analyst's answer, there is no problem if x is 1x8 before your loop.
Noru
Noru am 27 Mär. 2013
i think i ask the wrong question..
thanks for your help.. :))

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (1)

Image Analyst
Image Analyst am 21 Mär. 2013
I got a different error message due to x not being predefined and your new x(ii) depends on your old x(ii). When I predefined x, it ran with no errors:
x = zeros(1, 8);
for ii = 1:8
nilai = mod(ii,2);
if nilai == 0
x(ii) = 0.95 + (1.05-0.95)*x(ii);
elseif nilai ~= 0
x(ii) = round(3 + (30-3)*x(ii));
elseif nilai ~= 0
x(ii) = 0.01 + (0.055-0.01)*x(ii);
else
x(ii) = 1.0 + (1.15-1.0)*x(ii);
end
end
x = reshape(x,4,2)'
In the command window:
x =
3 0.95 3 0.95
3 0.95 3 0.95
  2 Kommentare
Noru
Noru am 21 Mär. 2013
now i already done create a matrix like you do, but i want to make the value of the 3rd column like 2nd and 4th(non integer number) like below
x =
8 0.67 0.32 0.76
14 0.49 0.21 0.53
do you have any solution..?
Image Analyst
Image Analyst am 21 Mär. 2013
% make the value of the 3rd column like 2nd
x(:,3) = x(:,2);
% make the value of the 3rd column like 4th
x(:,3) = x(:,4);

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu Lighting, Transparency, and Shading finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by