Output of function not variable I assign

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Kyle
Kyle am 17 Mär. 2013
When I run this function I want that vector to be called u so I can use it in another script file. Instead it calls it "ans" which I can't use. What is going on? Here is the function, just run it for n=4.
function [u]=finitevolume_KG(n)
%n is the number of volumes
delta_x = 1/n;
A=zeros(n-1);
A(1,1)=1;
A(1,2)=-1;
for i=2:n-2
A(i,i-1)=-1;
A(i,i)=2;
A(i,i+1)=-1;
end
for i=n-1
A(i,i-1)=-1;
A(i,i)=2;
end
f=ones(n-1,1);
f_x=((delta_x)^2)*f;
u = (A)\(f_x);

Antworten (2)

per isakson
per isakson am 17 Mär. 2013
Bearbeitet: per isakson am 18 Mär. 2013
Try the call
u = finitevolume_KG( 4 )
and make it a habit to end your functions with the keyword "end".
  2 Kommentare
Jan
Jan am 18 Mär. 2013
I still omit the trailing "end" to support the small part of Matlab 6.5 users.
per isakson
per isakson am 19 Mär. 2013
Yes, but "end" kind of indicates the end of the workspace of the function.

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Jan
Jan am 18 Mär. 2013
Some simplifications:
function u = finitevolume_KG(n)
%n is the number of volumes
delta_x = 1/n;
A = zeros(n-1, n-1);
A(1,1) = 1;
A(1,2) = -1;
A(2:n-2, 1:n-3) = -1;
A(2:n-2, 2:n-2) = 2;
A(2:n-2, 3:n-1) = -1;
A(n-1, n-2) = -1;
A(n-1, n-1) = 2;
u = A \ (delta_x ^ 2 * ones(n-1, 1));

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