how can I organize an array removing null elements and keep the same structure

Hello, everything okay?

if

A=[0 2 3 4 0 6;

0 6 8 10 0 10]

end if wont to

B= [2 3 4 6;

6 8 10 10]

Answer 1

[Image Analyst]

Try all():

A=[0	2	3	4	0	6;
	0	6	8	10	0	10]

columnsToKeep = any(A ~= 0, 1)
A = A(:, columnsToKeep)

If there are not the same number of zeros in each row, then that column will not be deleted. Only columns where every element in the column is 0 will be deleted. If you have the same number or zeros in each row but they occur in ndifferent columns, then you'd need

A=[ 2 	0	3	4	0	6;
	0	6	8	10	0	10]
[rows, columns] = size(A)
numZeros = sum(A(1,:) == 0)
output = zeros(rows, columns - numZeros)
for row = 1 : rows
	thisRow = A(row, :);
	output(row, :) = thisRow(thisRow ~= 0);
end

[Fidele Adanvo]

thank you