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I need the Solution of this equation
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If
E=1:0.5:10;
A=2.5;
B=3.18;
C=4.25;
D=0.15;
then
S = A + B*(lnE/E)+ C*(lnE/E)^2 + D*(E/lnE)
3 Kommentare
Antworten (6)
Azzi Abdelmalek
am 3 Mär. 2013
syms A B C D E lnE
s=solve(A + B*(lnE/E)+ C*(lnE/E)^2 + D*(E/lnE),lnE)
E=1:0.5:10;
A=2.5;
B=3.18;
C=4.25;
D=0.15;
out=subs(s)
0 Kommentare
Youssef Khmou
am 3 Mär. 2013
hi,
A=2.5;
B=3.18;
C=4.25;
D=0.15;
f=@(E) A + B.*(log(E)./E)+ C.*(log(E)./E).^2 + D*(E./log(E))
E=1:0.5:10;
figure, fplot(f,E)
fsolve(f,0)
0 Kommentare
Matt J
am 3 Mär. 2013
Bearbeitet: Matt J
am 3 Mär. 2013
I need to fill in a few blanks for myself. If I assume that E is the unknown to solve for (your post seems to say it is a vector of data) and S is supposed to be zero (your post doesn't specify), then there are no real solutions. Your equation is quadratic in lnE/E with roots
>> r=roots([C,B-D,A])
r =
-0.3565 + 0.6791i
-0.3565 - 0.6791i
0 Kommentare
dashty
am 4 Mär. 2013
3 Kommentare
Jan
am 4 Mär. 2013
@dashty: "no answer is correctly" is not helpful. 1. It is not clear which answer are concerned by this question, because some answers could be posted afterwards. Of course I can compare the date and time of the answers manually, but this wastes the time of all who want to help you. 2. Instead of mentioning, that they are not correct, a detailed description between the results and your expectations would help to improve the answers. Currently the quality of the answers exceed the information density of the question. Please do not let us guess, what you want.
Azzi Abdelmalek
am 4 Mär. 2013
This is not an equation:
A=2.5;
B=3.18;
C=4.25;
D=0.15;
E=1:10
S=A + B*(log(E)./E)+ C*(log(E)./E).^2 + D*(E./log(E))
0 Kommentare
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