logic in matlab to filter result

5 Ansichten (letzte 30 Tage)
ali hassan
ali hassan am 18 Nov. 2020
Bearbeitet: Image Analyst am 19 Nov. 2020
HELLO everyone.
i have a little query,.plzz answer in brief for better understanding.
actually i am getting the following two solutions as mentioned in each column as x,y and z.now i want to only keep the column in which value of z(bottom value) is positive.
plzz correct the code and mention it in comments.
CODE:
idx = any(possibleSol < 0) | any(imag(possibleSol) ~=0);
possibleSol(:, idx) = [ ];
BEST REGARDS

Akzeptierte Antwort

Image Analyst
Image Analyst am 18 Nov. 2020
Try this
% Extract z from the last row of possibleSol.
z = possibleSol(3, :);
% Find out which columns have the last row (z) as positive.
goodColumns = z > 0;
% Extract only those columns where z > 0
possibleSol = possibleSol(:, goodColumns)
  3 Kommentare
Image Analyst
Image Analyst am 18 Nov. 2020
Bearbeitet: Image Analyst am 19 Nov. 2020
You can read : as basically "all rows". And idx is just a bad name for the variable -- it should be called goodIndexes or something much more descriptive than idx. Don't you just hate it when people use confusing, cryptic variable names? Anyway idx is a logical vector that says, for each element, whether to extract that column or not. For example
m = m(:, [1,1,0,0,1]);
would say to take all rows of m, but only columns 1, 2, and 5 and put those 3 extracted columns back into m.
Conversely, if I said
m(:, [1,1,0,0,1]) = [];
it says to remove columns 1, 2, and 5 by setting them equal to "null", or "empty", which is indicated by the two square brackets with nothing inside. So after that matrix m would contain only columns 3 and 4.

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by