Creating a matrix row by row with for loop how?

So I'm trying to figure out a way to create a matrix of x by y. Say x =[1 2 3 ] and y = [5 6 7 9 10 11]. I'm trying to get my script to shift the longest array y,to the right according to the length of x. So my matrix would look like this:

Newy =[5 6 7 8 9 10 11 0 0;

       0 5 6 7 8 9 10 11 0; 

       0 0 5 6 7 8 9 10 11].

I know how to iterate the y array in respect to the length of x by doing :

y(mod((1:end)-i-1,end)+1)

I just can't figure out how to create a matrix row by row, I tried:

 y1=[y    zeros(1,length(x)-1)];

 For i= 0:length(x)-1

    y1(i,:) =y(mod((1:end)-i-1,end)+1);

But I keep generating errors . Any help would be much appreciated!

[Azzi Abdelmalek]

y = [5 6 7 9 10 11].

Why |[5 6 7 8 9 10 11 0 0; ?

Answer 1

[Image Analyst]

Try this:

x =[1 2 3 ]
y = [5 6 7 9 10 11]
ly = length(y);
y1 = zeros(length(x), max(x)+ly-1)
for row = 1 : length(x)
  y1(row, x(row):x(row)+ly-1) = y;
end
y1

In the command window:

y1 =
     5     6     7     9    10    11     0     0
     0     5     6     7     9    10    11     0
     0     0     5     6     7     9    10    11

(I hope I'm not allowing you to cheat by doing your homework for you!)

Answer 2

[jessy]

Thanks a lot!i just couldn't wrap my head around it this really helped.

[Image Analyst]

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