Given a matrix A replace elements not equal 0 and not equal 1 by 5. Use disp() function to print out the resulting array.
So far I've got
A(A~=0) = 5;
disp(A);
but do not know how to make it 0 AND 1.

2 Kommentare

KSSV
KSSV am 27 Okt. 2020
When you use ~=0 and replace those with 5, the elements whch have 1 also will be eplaced by 5 right?
Liam Bouchereau
Liam Bouchereau am 27 Okt. 2020
Yeah so all elements that don't = 1 or 0 need to be replaced by the element 5

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 Akzeptierte Antwort

Sudhakar Shinde
Sudhakar Shinde am 27 Okt. 2020
Bearbeitet: Sudhakar Shinde am 27 Okt. 2020

0 Stimmen

Try this:
A((A>1)|(A<0))=5

5 Kommentare

Sudhakar Shinde
Sudhakar Shinde am 27 Okt. 2020
But here is a question why you would like to do this operation? At the last you know all the elements will be '5' in result if need to use both the conditions.
Liam Bouchereau
Liam Bouchereau am 27 Okt. 2020
Oh no, so I want to replace all elements that don't equal 1 or 0. So the array should be made up of 0's 1's and 5's like so...
A = [-1 0 4 6; 1 1 0 2; -7 0 5 0; 5 1 5 1];
would become
A = [5 0 5 5 1 1 0 5 5 0 5 0 5 1 5 1]
Then you can simply use:
A((A>1)|(A<0))=5
Liam Bouchereau
Liam Bouchereau am 27 Okt. 2020
Thankyou
Sudhakar Shinde
Sudhakar Shinde am 27 Okt. 2020
Welcome

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Weitere Antworten (1)

Stephen23
Stephen23 am 27 Okt. 2020
Bearbeitet: Stephen23 am 27 Okt. 2020

0 Stimmen

Use AND instead of OR:
>> A = [-1,0,4,6;1,1,0,2;-7,0,5,0;5,1,5,1]
A =
-1 0 4 6
1 1 0 2
-7 0 5 0
5 1 5 1
>> A(A~=0&A~=1) = 5
A =
5 0 5 5
1 1 0 5
5 0 5 0
5 1 5 1

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