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How to make a loop through each row?

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Daria Ivanchenko
Daria Ivanchenko am 21 Okt. 2020
Kommentiert: David Hill am 21 Okt. 2020
Hi! I have a variable A in the size of 50x15000 with different numbers. And I have variable B, the same size 50x15000, that has only zeros and ones. I want to filter the data in the variable A based on variable B, and put the result in variable C. I need to take the numbers from A only if it is zero in the matrix B. One row is one trial in both A and B.
I wrote a small for loop:
C = NaN(size(A));
for i = 1:size(A,1)
C(i,:) = A(i, B(i,:) == 0);
end
The problem is that, after filtering the data, each row has different number of columns, so it doesn't want to be in one matrix. I have a message like this: "Unable to perform assignment because the size of the left side is 1-by-15000 and the size of the right side is 1-by-13683".
How can I solve this problem?
Thank you!
  2 Kommentare
Stephen23
Stephen23 am 21 Okt. 2020
"How can I solve this problem?"
Which would you prefer?:
  • a matrix padded with NaN (or some other value).
  • a container array (e.g. cell array) of vectors.
Daria Ivanchenko
Daria Ivanchenko am 21 Okt. 2020
A matrix padded with NaN would be better!

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Antworten (1)

David Hill
David Hill am 21 Okt. 2020
Bearbeitet: David Hill am 21 Okt. 2020
Make C a cell array
for i = 1:size(A,1)
C{i} = A(i, B(i,:) == 0);
end
  2 Kommentare
Daria Ivanchenko
Daria Ivanchenko am 21 Okt. 2020
Yes, this works, thanks, but it is really necessary for me to have all in one matrix and not in differents cells.
David Hill
David Hill am 21 Okt. 2020
C=zeros(size(A));
C(B==0)=A(B==0);
C(B==1)=nan;

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