calculating simple 2 equations with matlab. give me matlab code please~~

Answer 1

[KSSV]

That is pretty simple.....I will give some demo example..you have to extend it to your case.

Say got give f I want to find y = log(1/(sqrt(2)*pi*f))

f = 2 ;
y = log(1/(sqrt(2)*pi*f))

[whiyan]

yes but with my calculator answer and matlab answer are different.

Maybe some order was wrong. But still dont know what is correct.

Can you give some code?

[KSSV]

Show us your MATLAB code..so that we can correct you.

[whiyan]

f=20;

y=20*log(1/sqrt(1+(2*pi*f*(102*10^-9)*(985.1))^2)

i wrote the code for the first equation. Can you look over is it correct?

[Alan Stevens]

Note that log in MATLAB is log to the base e. It's possible your calculator uses log to mean log to base 10.

[John D'Errico]

My bet? What is the difference between log, and log10? I know, just a factor of the natural log of 10.

But many times when someone writes log, they think they mean log to the base 10.

[KSSV]

You have missed a bracket in the lines which you have given.

f=20;
y=20*log(1/sqrt(1+(2*pi*f*102*10^-9*985.1)^2))