one script two anonymous functions

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alessia luffarelli
alessia luffarelli am 13 Okt. 2020
Verschoben: Image Analyst am 6 Nov. 2022
I do not undestand when I wrong in my code
thank you so much for yor help
ThirdSide = @(a,b,C) sqrt(a^2+b^2-(2*a*b*cos(C)));
TriangleArea = @(a,b,C) ((a*b)/2)*sin(C);
SideC =ThirdSide(5,8,50*pi/180)
AreaABC=TriangleArea(5,8,50*pi/180)

Antworten (2)

Steven Lord
Steven Lord am 13 Okt. 2020
Based on the problem description I'm guessing C is an angle in degrees, not radians. If that's the case take a look at the sind function.

Fanele
Fanele am 6 Nov. 2022
Verschoben: Image Analyst am 6 Nov. 2022
ThirdSide=@(a,b,C) sqrt(a^2+b^2-2*a*b*cos(C*pi/180))
ThirdSide = function_handle with value:
@(a,b,C)sqrt(a^2+b^2-2*a*b*cos(C*pi/180))
TriangleArea=@(a,b,C) (((a*b)/2)*sin(C*pi/180))
TriangleArea = function_handle with value:
@(a,b,C)(((a*b)/2)*sin(C*pi/180))
SideC=ThirdSide(5,8,50)
SideC = 6.1300
AreaABC=TriangleArea(5,8,50)
AreaABC = 15.3209

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