check if an array is equispaced

I am given a vector of numbers and I have to check if this vector has its samples equispaced or not. How can I do it without using fors?

Answer 1

[Ameer Hamza]

Something like this

x = [1 2 3];
dx = diff(x);
is_equidistant = all(dx==dx(1));

Result

>> is_equidistant
is_equidistant =
  logical
   1

If

x = [1 2 5];
dx = diff(x);
is_equidistant = all(dx==dx(1));

Result

>> is_equidistant
is_equidistant =
  logical
   0

If you want to check it with a tolerance value

x = [1 2 3.00000000000001];
dx = diff(x);
is_equidistant = all(ismembertol(dx, dx(1)));

Result

>> is_equidistant
is_equidistant =
  logical
   1

[Mireia Boneta Camí]

thank you very much!!!

Answer 2

[Stephen23]

>> v = [1,2,3,4,5,6,7];
>> x = ~any(diff(v,2))
x = 1
>> v = [1,2,4,4.5,7];
>> x = ~any(diff(v,2))
x = 0

[Mireia Boneta Camí]

thanks too!