Using sign(x) with -0.00?

Hi, I need to go through a vector and check the sign of an oscillatory function but I have a lot of -0.0000's at the start which is going to mess up what I need to do.
Is there anyway to convert them to 0.000 rather than -0.000?
Thanks

 Akzeptierte Antwort

Jan
Jan am 31 Jan. 2013
Bearbeitet: Jan am 31 Jan. 2013

0 Stimmen

Matlab does not have a -0.0, therefore what you are seeing must be a -0.000000000000001 or similar, which is hidden by the display format. To see more digits type this in the command window:
format long g
If you have good reasons to claim, that these data are pure noise, you can smooth it:
x(abs(x) < 1e-10) = 0.0;
But be sure to note the physical motivation of the threshold value.

5 Kommentare

Martin
Martin am 31 Jan. 2013
cheers, this worked a treat. I was already using the format long command. What does the extra 'g' do?
Turns out it was something like 1e-29 so pretty small!
José-Luis
José-Luis am 31 Jan. 2013
Please accept an answer if it helps you.
Walter Roberson
Walter Roberson am 31 Jan. 2013
"g" means to choose the best representation automatically.
Jan
Jan am 31 Jan. 2013
Or to explain "best": the "e" notation is used, when it can display more significant digits than the 0.0000xyz notation.
James Tursa
James Tursa am 31 Jan. 2013
Bearbeitet: James Tursa am 31 Jan. 2013
To clarify what Jan wrote, IEEE double and single floating point (which MATLAB uses) do in fact have distinct -0.0 bit representations (sign bit set to 1 and all other bits reset to 0) that is different from 0.0 (all bits reset to 0). But by default MATLAB will not display the minus sign '-' for these numbers, so when you see something like -0.0000 printed to the screen it is not really a -0.0 value. Rather it represents a small negative number compared to the other numbers that were printed to the screen at the same time (there simply weren't enough digits printed to show the non-zero digits of the small negative number). To see this type the following at the MATLAB prompt:
format hex
0
-0
0 == -0
typecast(0,'uint64') == typecast(-0,'uint64')

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Weitere Antworten (1)

José-Luis
José-Luis am 31 Jan. 2013

0 Stimmen

your_mat(abs(your_mat) < 100*eps) = 0; %or some other limit

1 Kommentar

Martin
Martin am 31 Jan. 2013
This looks like a good thing to do also, thanks. For all intents and purposes the numbers I am getting -0.00000 for could be equated to zero.

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