matrix creation from a loop
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Hello all,
I would like to create 60 vector columns of zeros (6964,1) called lat_01_days, lat_02days, lat_03_days until 60. I know I could write them one by one but if i know How to create a loop to create them it would be better also for future research. Can someone help mep lease?
regards
Jonathan
2 Kommentare
Stephen23
am 17 Sep. 2020
"I would like to create 60 vector columns of zeros (6964,1) called lat_01_days, lat_02days, lat_03_days until 60."
Numbering variables like that is a sign that you are doing something wrong.
Forcing meta-data (e.g. pseudo-indices) intoe variable names is a sign that you are doing something wrong.
"I know I could write them one by one ..."
Ouch!
"...but if i know How to create a loop to create them it would be better also for future research"
In fact what "would be better also for future research" is to avoid numbered variables entirely:
Antworten (3)
Walter Roberson
am 17 Sep. 2020
if i know How to create a loop to create them it would be better also for future research.
Our long experience is that it would make your future research worse instead of better.
Stephen23
am 17 Sep. 2020
The simplest and most efficient solution is to just create one matrix:
lat = zeros(6964,60)
which you can then trivially access using indexing. There is no point in making it more complex than that.
0 Kommentare
Ruger28
am 17 Sep. 2020
Bearbeitet: Ruger28
am 17 Sep. 2020
The two other answers are a more correct way of doing it. There is no need to create this many variables in your workspace. However, if you must...
You should use a structure instead of individual variables.
Blank_Vec = zeros(6964,1);
Num_Cols = 60;
for ii = 1:Num_Cols
name = sprintf('lat_%i_days',ii);
ZeroColStruct.(name) = Blank_Vec;
end
if you absolutely MUST have individual variables, one method is this:
% Removed due to being a terrible way to do something
3 Kommentare
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