how to construct this equation in matlab?..for loop is best r something else..?
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http://latex.codecogs.com/gif.latex?H'_{i+1}(x,y)=round(\frac{H_{i}(2x-1,2y-1)+H_{i}(2x,2y-1)+H_{i}(2x,2y)}{4})-H_{i+1}(x,y)...
where i values varies 1 and 2.
x and y vale is 51 and 56 if i=1 ,i=2 mean x and y value is 76 and 78
[Merged from duplicate question]
http://latex.codecogs.com/gif.latex?H'_{i+1}(x,y)=round(\frac{H_{i}(2x-1,2y-1)+H_{i}(2x,2y-1)+H_{i}(2x,2y)}{4})-H_{i+1}(x,y)
for this equation i wrote this code.
x=51;
y=52;
H2'(x,y)=((H1(2x-1,2y-1)+H1(2x-1,2y)+H1(2x,2y)))/4
P=H2(x,y);
Q=H2'(x,y-H2(x,y);
here first of all H represents a horizontal subband of image 128 x 128. from this i'am derive detailed subbands H1,H2,H3. values 51 52,76 76,88 88. "i" values varies from 1 and 2.
5 Kommentare
Jan
am 21 Jan. 2013
What have you tried so far and which problems occurred?
Dhines
am 22 Jan. 2013
Roger Stafford
am 22 Jan. 2013
Bearbeitet: Roger Stafford
am 22 Jan. 2013
Please give us a lot more information, Prasanna. You know we can't help you with the little information you have given. What do you mean by "construct this equation"? Explain the significance of that equation. What does the "prime" mark on H indicate? Give us all the details.
Dhines
am 22 Jan. 2013
Walter Roberson
am 22 Jan. 2013
[New question has been merged into the original.]
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