sum of function handles
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Hi, i want to sum two function handle. the functions that i want to sum are following;
f1=0;
for i=1:20
f2=f2(x(1),x(2),x(3))
f1=f1+f2
end
how can i do by using function handle? the following is true?
f1=@(x)(0);
for i=1:20
f2=@(x)(f2(x(1),x(2),x(3)))
f1=@(x)(f1(x)+ f2(x));
end
Can anyone help me? Because i use this last summation function for fminsearch
3 Kommentare
Jan
am 16 Jan. 2013
@dert: Please do not cross post. Posting a question in several forums at the same time wastes the time of the voluntary helpers.
Walter Roberson
am 16 Jan. 2013
Antworten (2)
Thorsten
am 16 Jan. 2013
Do you want to evaluate f2 20 times and store the summed result in f1? Than you can use this:
f1 = 0;
for i=1:20
f1 = f1 + f2(x(1),x(2),x(3));
end
Otherwise, please explain what you want to do.
0 Kommentare
Umar Ceres
am 20 Nov. 2023
So this thread is quite old and seems nobody has posted a method to sum function handles and have a resulting anonymous function. See the following:
a1 = @(x) x(1).^2 + x(2).^2;
a2 = @(x) x(1) + x(2);
syms x [1 2] matrix
a = a1(x) + a2(x)
a_syms = symmatrix2sym(a)
a_anon = matlabFunction(a_syms)
1 Kommentar
Dyuman Joshi
am 20 Nov. 2023
@Umar Ceres, How will you proceed with the same method if a1 and a2 are defined as follows -
a1 = @(x) sum(x(1:randi(numel(x))).^2);
a2 = @(x) sum(x(1:randi(numel(x))));
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