Akzeptierte Antwort

Image Analyst
Image Analyst am 16 Jul. 2020

0 Stimmen

You need to define LastName. How should your program know what it is? It's not a built in function or anything.

2 Kommentare

abdul rehman
abdul rehman am 16 Jul. 2020
can you please tell a bit of code please, thanks
Try this:
t = readtable('patients.xls')
tNew = t(1:5, :) % Extract first 5 rows only.
% Get a LastName variable from column 1
LastName = tNew{:, 1}
tNew.Properties.RowNames = LastName'
tNew =
5×10 table
LastName Gender Age Location Height Weight Smoker Systolic Diastolic SelfAssessedHealthStatus
____________ __________ ___ _____________________________ ______ ______ ______ ________ _________ ________________________
Smith {'Smith' } {'Male' } 38 {'County General Hospital' } 71 176 true 124 93 {'Excellent'}
Johnson {'Johnson' } {'Male' } 43 {'VA Hospital' } 69 163 false 109 77 {'Fair' }
Williams {'Williams'} {'Female'} 38 {'St. Mary's Medical Center'} 64 131 false 125 83 {'Good' }
Jones {'Jones' } {'Female'} 40 {'VA Hospital' } 67 133 false 117 75 {'Fair' }
Brown {'Brown' } {'Female'} 49 {'County General Hospital' } 64 119 false 122 80 {'Good' }

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by