[Solved] Upsampling multidimensional array with interpn
9 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Johnny Scalera
am 9 Jul. 2020
Bearbeitet: Johnny Scalera
am 10 Jul. 2020
Hi all,
I'm trying to upsample a multidimensional array. Here is the code that I used for a monodimensional array:
sf1 = 100; %original sampling frequency
time = (0:(1/sf1):10-(1/sf1))'; %time array
x = randn(length(time), 1);
sf2 = 200; %final sampling frequency
upTime = (0:(1/sf2):10-(1/sf2))';
y = interp1(time, x, upTime);
Now I would like to upsample a 5D array, such as:
z = [randn(length(time), 1) randn(length(time), 1) randn(length(time), 1) randn(length(time), 1) randn(length(time), 1)];
How Can I use the interpn function properly?
Thank You all!
0 Kommentare
Akzeptierte Antwort
John D'Errico
am 9 Jul. 2020
Bearbeitet: John D'Errico
am 9 Jul. 2020
That is NOT a 5 dimensional array.
While you may THINK of it as a set of points that live in 5 dimensions, it is NOT a 5-d array. You CANNOT use interpn to interpolate that data. NOT. Period. NOT.
THIS is a 5-dimensional array:
A = rand(2,3,4,5,6);
size(A)
ans =
2 3 4 5 6
You can then use tools like griddatan or scatteredInterpolant to interpolate such data.
If you want to view the data as 5 independent streams of ONE dimensional data, then you can still use interp1 to interpolate. For example:
A = rand(100,5);
t = (1:100)';
interp1(t,A,7.25)
ans =
0.35284 0.051081 0.32818 0.34913 0.75639
Only you know what the array represents. By themselves, numbers are just numbers. Only you know what they represent.
2 Kommentare
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Interpolation finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!