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Shuffling numbers while keeping identical numbers next to each other

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Hi everyone,
Let us assume the following array:
A = [1 1 2 3 3 4 6 6 6 6]
I would like to shuffle this array while while keeping identical numbers next to each other (e.g., array B):
B = [1 1 3 3 6 6 6 6 4 2]
This means that array C is not desirable for me:
C = [1 3 1 3 6 4 6 2 6 6]
Do you have any suggestion?
Regards,
Amir

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Accepted Answer

Stephen Cobeldick
Stephen Cobeldick on 8 Jul 2020
Edited: Stephen Cobeldick on 8 Jul 2020
>> A = [1,1,2,3,3,4,6,6,6,6];
>> X = diff(find([1,diff(A),1]));
>> C = mat2cell(A,1,X);
>> Y = randperm(numel(C));
>> V = [C{Y}]
V = 2 1 1 6 6 6 6 3 3 4

  2 Comments

Amirhossein Moosavi
Amirhossein Moosavi on 8 Jul 2020
Thanks! It works. One more question. What if I have another array (identical size) and want to shuffle it with the exact same order? For example:
A = [1 1 2 3 3 4 6 6 6 6]
B = [1 2 3 4 5 6 7 8 9 10]
Now, assume that I have shffuled A as follows:
A = [6 6 6 6 1 1 2 3 3 4]
Accordingly, array B must be sorted as follows:
B = [7 8 9 10 1 2 3 4 5 6]
Thanks in advance!
Stephen Cobeldick
Stephen Cobeldick on 8 Jul 2020
To sort the 2nd vector into the same order you could split and recombine just like we did for the 1st, e.g.:
D = mat2cell(B,1,X);
Bout = [D{Y}]
But if you need to do this for quite a few vectors, simply generate the indices:
D = mat2cell(1:numel(A),1,X);
Z = [D{Y}];
and then use those indices as often as required:
Bout = B(Z);

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