3D plotted shape is not following curvature of data points
3 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Sumeet Chaudhari
am 6 Jul. 2020
Bearbeitet: John D'Errico
am 6 Jul. 2020
I am writing a code that creates a 3D shape from a set of data points and am running into this problem where the shape does not properly follow the curvature of the data points and rather draws a straight line. This can be seen on the sides of the figure below where the shape isn't properly following the data points into the curves.
My code:
load('seg_info.mat');
x = seg_info(:, 1);
y = seg_info(:, 2);
z = seg_info(:, 3);
colors = seg_info(:, 4);
scatter3(x,y,z);
hold on;
DT = delaunayTriangulation(x, y, z);
[K, v] = convexHull(DT);
trisurf(K, DT.Points(:,1), DT.Points(:,2), DT.Points(:,3), ...
'FaceAlpha', 0.5, 'EdgeColor', 'none', ...
'CData', colors, 'FaceColor', 'interp');
Does anyone know how I can improve my code to better fit these sides? I have tried using alpha shapes and boundary in an attempt to derive the concave hull but neither worked.
5 Kommentare
John D'Errico
am 6 Jul. 2020
You think the problem is in the triangulation? A delaunay triangulation trinagulates the entire region within the convex hull of the data. In fact, you even used a convex hull there. So surely you would expect that the result will be a convex region. If you don't want it to be convex, then you can't use a convex hull. Or for that matter, a Delaunay triangulation.
Akzeptierte Antwort
jonas
am 6 Jul. 2020
2 Kommentare
John D'Errico
am 6 Jul. 2020
Bearbeitet: John D'Errico
am 6 Jul. 2020
Assuming that is a CRUST implementation, it is probably the best choice. And a quick glance at the code suggests it is indeed CRUST.
An alternative code can be found here:
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Bounding Regions finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!