Fourier Transform of tripuls

Below you got what I've tried, but it does not work. The second graph does not match with the actual fft of a triangle function. Can someone help me? The use of tripuls is required! Ty!

clc
t=-2:.01:2;
subplot(2, 1, 1);
x=tripuls(t,2);
plot(t, x);
title('Triangle');

subplot(2, 1, 2);
Ts = mean(diff(t));                                     % Sampling Interval
Fs = 1/Ts;                                              % Sampling Frequency
Fn = Fs/2;                                              % Nyuquist Frequency
L = length(x);
ftx = fft(x)/L;                                         % Fourier Transform
ftxs = fftshift(ftx);                                   % Shift To Centre                                 
plot(t, ftxs);
title('TdF Triangle');

Answer 1

[Priyanshu Mishra]

Hi Moisa,

fft is giving you a complex double values . Try taking only absolute values. I tried the following code and getting sinc squared function which is expected for a triangular pulse.

clc

t=-2:.01:2;

subplot(2, 1, 1);

x=tripuls(t,2);

plot(t, x);

title('Triangle');

subplot(2, 1, 2);

Ts = mean(diff(t)); % Sampling Interval

Fs = 1/Ts; % Sampling Frequency

Fn = 2*Fs; % Nyuquist Frequency

L = length(x);

ftx = abs(fft(x)); % Fourier Transform

ftxs = fftshift(ftx); % Shift To Centre

plot(t, ftxs);

title('TdF Triangle')