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Accessing a individual value within a table

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Frank Lehmann
Frank Lehmann am 10 Jun. 2020
Beantwortet: Frank Lehmann am 10 Jun. 2020
Hi All,
I have a basic ? which i just cannot find a solution. I have a 18 x11 table which i narrowed down to a paricular row and column but cannot evaluate the particular value from the column in this case 104. I want this value as a double so I can do further calculations on the output. Any ides on how to acheive this with the minimum code syntax? Part of the code is listed below after inputting the array and also a snapshot from the command window to my final otuput but stuck at getting the desired output of (14) for further manipulation. Any ideas am I missing something?
A1=array2table(A1);
A1.Properties.VariableNames = {'CSA' 'R_1C' 'R_MC' 'X_1C' 'X_MC' 'AG_1C' 'AG_MC' 'DB_1C' 'DB_MC' 'BC_1C' 'BC_MC'};
ct=cellstr(ct);
ccd = strcat(ci, {'_'}, cc);
rows = A1.CSA == CSA;
CSA=A1(rows,:)
result=A1(rows,[ccd])
  1 Kommentar
Stephen23
Stephen23 am 10 Jun. 2020
Bearbeitet: Stephen23 am 10 Jun. 2020
You need to use the correct brackets for indexing:
  • () parentheses refers to the table itself
  • {} curly braces refer to the table contents

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Antworten (2)

Walter Roberson
Walter Roberson am 10 Jun. 2020
result = A1{rows,[ccd]}

Frank Lehmann
Frank Lehmann am 10 Jun. 2020
Thanks Walter and Stephen. Don't you just hate it when the answer is staring at you right in the face, DOH!!

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