input=[1 1 0 1 0 0 1 0 ]; %input bit
x1=bin2dec(num2str(11)); %converting number to characters
x2=bin2dec(num2str(01));
x3=bin2dec(num2str(00));
x4=bin2dec(num2str(10));
xx=[x1,x2,x3,x4];
This is my code, I don't want to use individual bin2dec conversion. How can I put it in 'for loop'?

 Akzeptierte Antwort

Stephen23
Stephen23 am 30 Mai 2020
Bearbeitet: Stephen23 am 30 Mai 2020

0 Stimmen

This is MATLAB, you don't need a for loop!
Method one: mtimes:
>> V = [1,1,0,1,0,0,1,0];
>> N = 2;
>> X = pow2(N-1:-1:0)*reshape(V,N,[])
X =
3 1 0 2
Method two: bin2dec:
>> V = [1,1,0,1,0,0,1,0];
>> N = 2;
>> X = bin2dec(reshape(sprintf('%u',V),N,[]).');
X =
3
1
0
2

3 Kommentare

Darshan Manjunathrao Chawan
Bearbeitet: Darshan Manjunathrao Chawan am 30 Mai 2020
But can't I put it in for loop to determine individual values. I need to understand properly, since I am a beginner.
Stephen23
Stephen23 am 30 Mai 2020
"But can't I put it in for loop to determine individual values"
Of course, you can use a loop if you want to. Try it.
Can you please help me with that?

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Mehr zu Convert Image Type finden Sie in Hilfe-Center und File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by