date and time convert in number

1 Ansicht (letzte 30 Tage)
Rica
Rica am 15 Nov. 2012
Hi
I have :
%
date vector:
a=['1.1.2010';'2.2.2010';'2.5.2010'...]
time vector:
b=['1.2.58';'2.5.52';'4.6.30'.....]
date_time=[a b]
i transform the vector from cell to array with cell2mat and i get
% ab=1.1.20102.2.58
2.2.20102.5.52
2.5.20104.6.30
how could i isert white space between date and time to be able to use datenum?
thank you

Akzeptierte Antwort

Jan
Jan am 15 Nov. 2012
Please note, that this definition will fail as soon as any day or month has more than 1 digit:
a = ['1.1.2010'; '2.12.2010'; '2.5.2010']; % ERROR! Different lengths!
For storing string of different size, a cell string is reuquired.
a = ['1.1.2010'; '2.2.2010'; '2.5.2010'];
b = ['1.2.58'; '2.5.52'; '4.6.30'];
c = strcat(cellstr(a), {' '}, cellstr(b));

Weitere Antworten (2)

Sara
Sara am 15 Nov. 2012
%date vector:
a={'1.1.2010';'2.2.2010';'2.5.2010'}
% time vector:
b={'1.2.58';'2.5.52';'4.6.30'}
date_time=[a b]

Rica
Rica am 15 Nov. 2012
hi!
but you could not use datenum(date_time)!

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