How to find factorial(c) of an array of numbers?
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
surabhi sachdeva
am 26 Mai 2020
Kommentiert: surabhi sachdeva
am 27 Mai 2020
Respected all
I have successfully got the values for j and v. I have got stuck in solving t due to the problem in finding factorial(c). My question is how to code for factorial term in the expression? Is it possible or I am on the wrong path? As without solving factorial, t cannot be determined. What should I do?
Code attached:
A = linspace(1,10)
C = linspace(1, 11)
[k, c] = ndgrid(A, C)
j=gammainc(c,(0.85));
v=gamma(c.^(-1));
t=0.85.*(1-(((0.85).^5.*(1-(((0.85))./(1-(((0.85)).^6)))))).*1.*(1-((0.85).^5.*(factorial(c)).^-1.*(c.^(5-c).^-1)./(exp(0.85).*k.*v+(0.85).^c.*(1-(0.85./c).^(5-c+1)))/factorial(c).*(1-(0.85./c)))));
The following error is being encountered
Error using factorial
N must be an array of real non-negative integers.
How can this error be removed?
Please help
Regards
Surabhi
0 Kommentare
Akzeptierte Antwort
Adam Danz
am 26 Mai 2020
Bearbeitet: Adam Danz
am 26 Mai 2020
N must be an array of real non-negative integers.
To troubleshoot that error message, let's go through the list of possibilities.
% Is c an array or real numbers?
all(isreal(c(:))) % = 1, true
% Is c all non-negative?
all(c(:)>=0) % = 1, true
% Is c all integers?
all(isinteger(c(:))) % = 0! FALSE
There's the problem. C contains non-integers. It makes sense that this would cause an error, right? Factorials are functions of intergers.
factorial(3) = 24
4 * 3 * 2 * 1 = 24
How could that be done with non-integers?
9 Kommentare
Adam Danz
am 27 Mai 2020
Glad I could help. If you get stuck again with this topic, leave a comment to loop me back in.
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Get Started with MATLAB finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!