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NN
NN am 8 Nov. 2012

2 Stimmen

Might help
Imagearray=double(imread('image's name (path).Image type e.g. tiff'));

2 Kommentare

Elysi Cochin
Elysi Cochin am 8 Nov. 2012
Thanks all
Image Analyst
Image Analyst am 8 Nov. 2012
Or maybe when you say write you mean imwrite to write the image array out to disk:
imwrite(yourImage, filename);
Using precise unambiguous terminology is important if you want a precise answer.

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Weitere Antworten (3)

Harshit
Harshit am 8 Nov. 2012

0 Stimmen

Why do you wanna write an image into an array. Use reshape if you really want.
Walter Roberson
Walter Roberson am 8 Nov. 2012

0 Stimmen

get() the CData property of the image; that will be an array.
Mohammed Manna
Mohammed Manna am 8 Nov. 2012
Bearbeitet: Mohammed Manna am 8 Nov. 2012

0 Stimmen

Simply do this
targetImg = imread("path");
targetImg = targetImg(:); % You can take a transpose too if you like
If you need to convert it to one of the primitive types, you can do so by
targetImg = double(targetImg);
targetImg = float(targetImg);
% etc.
If you have performance/speed/parallel processing related issues. I suggest you also look into get() CDATA property of the image. I am not sure why you need the array of an image. I must say that I cannot remember if about the float(). But the point is proven. Hope this helps you.

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