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i generate random numbers of x, how can i use this random x values for the rest of the code
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x = 0.05 + (0.1-0.05).*rand(10,1);
Perimeter = (pi*HydraulicDiameter);
NumberOfCoolantChannels = 3;
Npass = 1; ...Number of Passes
% Ac = (pi*(HydraulicDiameter^2)/(4)); ...Single channel flow cross section
Ac = 1.571e-5;
Atotal = NumberOfCoolantChannels*Ac; ... Total Flow Cross Section
BladeMassFlow = (CoolantBleed/100)*(TurbineMassFlow/NumberOfBlades);
ChannelMassFlow = (BladeMassFlow/NumberOfCoolantChannels);
RibHeighHydraulicDiameterRatio = x;
FrictionFactor2 = 1.447*(1.14-2*log10(x)).^-2; %transverse ribs
% OverallPressureDrop = FrictionFactor2*((Npass*BladeSpan*10^-3)/HydraulicDiameter)*CoolantDensity*((BulkVelocity^2)/2);
OverallPressureDrop = 8300;
BulkVelocity =((OverallPressureDrop/FrictionFactor2)*(HydraulicDiameter/(Npass*BladeSpan*10^-3))*(2/CoolantDensity))^0.5;
ChannelCoolantMassFlow = (CoolantDensity*Ac*BulkVelocity);
BladeCoolantMassFlow = NumberOfCoolantChannels*ChannelCoolantMassFlow;
PercentageCoolantBleed = 100*(BladeCoolantMassFlow*NumberOfBlades/TurbineMassFlow);
Re = (ChannelCoolantMassFlow/Ac)*(HydraulicDiameter/CoolantViscosity);
Nu = 0.15*Re^0.7; ...based on the Hydraulic Diameter
InternalHeatTransferCoefficient = Nu*(CoolantConductivity/HydraulicDiameter);
TechnologyFactor = (InternalHeatTransferCoefficient*Npass*Perimeter*NumberOfCoolantChannels)/(ExternalHeatTransferCoefficient*BladeExternalPerimeter*45*10^-3);
MassFlowFunction = (BladeCoolantMassFlow*CoolantSpecificHeat)/(BladeExternalPerimeter*BladeChord*10^-3*ExternalHeatTransferCoefficient*BladeSpan*10^-3);
ConvectionCoolingEfficiency = 1 - exp(-(TechnologyFactor)/(MassFlowFunction));
OverallEffectinevess = (MassFlowFunction*ConvectionCoolingEfficiency)/(1 + MassFlowFunction*ConvectionCoolingEfficiency);
MetalTemperature = (ExternalGasTemperature) - OverallEffectinevess*(ExternalGasTemperature-CoolantInletTemperature);
% FrictionFactor = 0.316*Re^-0.25; ...for smooth round pipe
% BulkVelocity = (ChannelMassFlow) / (CoolantDensity*Ac);
TemperatureSmooth = 1080.9;
TemperatureRipped = MetalTemperature;
RipEfficiency = ((TemperatureRipped-TemperatureSmooth)/TemperatureRipped)*100;
I am a new learner so could use show it or explain it very simply? the result i want to see is that rip efficiency and metal temperature.
5 Kommentare
dpb
am 19 Mai 2020
But there's no x in the equations...what variable(s) are you wanting randomized? You have to write the solutions in terms of the variables with some additional random component to see anything happen.
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