Distributing a cell array into another

1 Ansicht (letzte 30 Tage)
Jerki Jokne
Jerki Jokne am 18 Mai 2020
Beantwortet: Star Strider am 18 Mai 2020
If I have 2 cell arrays of chars, is it possible to distribute them such that they are combined and concatenated?
A = {'Category1', 'Category2'};
B = {'Mon', 'Tues', 'Wed', 'Thurs' 'Fri', 'Sat', 'Sun'};
Result = {'Category1 Mon', 'Category1 Tues', ..., 'Category1 Sun', 'Category2 Mon', 'Category2 Tues', ..., 'Category2 Sun'};

Akzeptierte Antwort

Star Strider
Star Strider am 18 Mai 2020
Adding end spaces to each character array in ‘A’ and converting them to string arrays:
A = {'Category1 ', 'Category2 '};
B = {'Mon', 'Tues', 'Wed', 'Thurs' 'Fri', 'Sat', 'Sun'};
then transposing ‘A’ and adding them:
Result = string(A).' + string(B)
produces:
Result =
2×7 string array
Columns 1 through 4
"Category1 Mon" "Category1 Tues" "Category1 Wed" "Category1 Thurs"
"Category2 Mon" "Category2 Tues" "Category2 Wed" "Category2 Thurs"
Columns 5 through 7
"Category1 Fri" "Category1 Sat" "Category1 Sun"
"Category2 Fri" "Category2 Sat" "Category2 Sun"
Otherwise, the only option is likely two nested loops, concatenating elements of ‘A’ and ‘B’ in each iteration to form elements of ‘Result’.
.

Weitere Antworten (2)

the cyclist
the cyclist am 18 Mai 2020
Bearbeitet: the cyclist am 18 Mai 2020
Here is a straightforward way:
A = {'Category1', 'Category2'};
B = {'Mon', 'Tues', 'Wed', 'Thurs' 'Fri', 'Sat', 'Sun'};
nA = numel(A);
nB = numel(B);
Result = cell(1,nA*nB);
nc = 0;
for ia = 1:nA
for ib = 1:nB
nc = nc + 1;
Result{nc} = [A{ia},' ',B{ib}];
end
end

Fangjun Jiang
Fangjun Jiang am 18 Mai 2020
strcat(repmat(A,size(B')),repmat({' '},[length(B),length(A)]),repmat(B',size(A)))

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