How can i write 2D longest character array ?
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
Oblique
am 16 Mai 2020
Kommentiert: Image Analyst
am 16 Mai 2020
This array must be between two asterisk signs (*) and the code should give us the longest name in this array
For example: {'878*jhon*23 ; '*jonathan*87' ; '485*will*421'}
output will be as a 'jonathan'
I wrote code like this. but it's not what want.
a = {'23*Ali*36' ; 'Veli*178' ; '99*Zeynep*'} ;
for k=1:length(a)
val(k)=length(a{k});
x = findstr(a) , '*' )
end
out=a(val==max(val)
0 Kommentare
Akzeptierte Antwort
Image Analyst
am 16 Mai 2020
Bearbeitet: Image Analyst
am 16 Mai 2020
Did you just try a super obvious brute force approach using a for loop:
a = {'23*Ali*36' ; 'Veli*178' ; '99*Zeynep*'} ;
nameLengths = zeros(length(a), 3); % Preallocate.
for k = 1 : length(a)
thisCellContents = a{k};
starLocations = find(thisCellContents == '*') % Find indexes of stars.
% Extract the name
if length(starLocations) >= 2
% Extract length between start #1 and star #2.
nameLengths(k, :) = [starLocations(1), starLocations(2), starLocations(2) - starLocations(1) + 1];
elseif length(starLocations) >= 1
% One star. Start from the beginning.
nameLengths(k, :) = [1, starLocations(1), starLocations(1)];
else
% No stars.
nameLengths(k, :) = [1, length(thisCellContents), length(thisCellContents)]; % The whole thing.
end
end
nameLengths % Report to command window.
[maxLength, row] = max(nameLengths(:,3)) % Find the longest one - biggest separation.
longestRow = a{row} % Get the entire string, including the start.
% Extract the substring.
out = longestRow(starLocations(1) + 1 : starLocations(2) - 1)
I'm sure there are less obvious, but more cryptic methods that are shorter if you want to wait for one from someone else.
4 Kommentare
Image Analyst
am 16 Mai 2020
You're welcome. Because comments are SO important, I added a few to make it even easier to follow. I encourage you to use descriptive variable names and lots of comments in your code. If my answer helped you maybe you could click the Vote button. Thanks in advance.
Weitere Antworten (1)
Ameer Hamza
am 16 Mai 2020
Bearbeitet: Ameer Hamza
am 16 Mai 2020
Try this
a = {'23*Ali*36' ; 'Veli*178' ; '99*Zeynep*'} ;
m = regexp(a, '[A-Za-z]*', 'match');
m = [m{:}];
[~, idx] = max(cellfun(@numel, m));
longest_name = m{idx};
Result
>> longest_name
longest_name =
'Zeynep'
5 Kommentare
Siehe auch
Kategorien
Mehr zu Octave finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!