Hi guys, can anyone help me with this please. Thanks.
So i have this Excel file. I filtered a column and then did some operations on the filtered data .
in the end, I wanna create a new matix, A, with the following characteristics. The matrix should have dimension: partID rows* 5 columns. First colum should contain the partID number (from 3 to 15), second column should contain the value of M associated with the partID, third column S, fourth m and fifth s.
how do i build A inside the cycle?

6 Kommentare

Turlough Hughes
Turlough Hughes am 15 Mai 2020
Can you share the file?
Murstoe
Murstoe am 15 Mai 2020
thanks you, Here is the file excel.
Turlough Hughes
Turlough Hughes am 23 Mai 2020
Murstoe, it's bad form to remove your question after being given an answer. Can you put it back?
Original question from Google Cache:
"Building a matrix inside a for loop"
Hi guys, can anyone help me with this please. Thanks.
So i have this Excel file. I filtered a column and then did some operations on the filtered data .
in the end, I wanna create a new matix, A, with the following characteristics. The matrix should have dimension: partID rows* 5 columns. First colum should contain the partID number (from 3 to 15), second column should contain the value of M associated with the partID, third column S, fourth m and fifth s.
how do i build A inside the cycle?
xlsData = xlsread('PartS_all.csv');
partID=xlsData(:,4);
for partID=3:15
tenpm=xlsData(xlsData(:,4)==partID,:);
part=sortrows(tenpm, 2); %Sort second column
M(partID)=mean(part(:,8));
S(partID)=std(part(:,8));
m(partID)=mean(part(:,11));
s(partID)=std(part(:,11));
A=
end
Murstoe
Murstoe am 23 Mai 2020
Guys I’m so sorry I don’t know what happened to it. I will sure fix it. I apologise again
Rena Berman
Rena Berman am 1 Jun. 2020
(Answers Dev) Restored edit

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Turlough Hughes
Turlough Hughes am 16 Mai 2020
Bearbeitet: Turlough Hughes am 16 Mai 2020

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You could do it as follows:
xlsData = xlsread('PartS_all.xlsx');
partID = xlsData(:,4);
uPartID = unique(partID).'; % Unique part IDs
% Preallocate space
c = 0;
A = zeros(numel(uPartID),5);
for currPartID = uPartID
c = c+1;
part = xlsData(xlsData(:,4) == currPartID,:); %edit
A(c,:) = [currPartID mean(part(:,8)) std(part(:,8)) mean(part(:,11)) std(part(:,11))];
end

2 Kommentare

Murstoe
Murstoe am 16 Mai 2020
I get the following error:
Index in position 2 exceeds array bounds (must not exceed 1).
Error in Untitled (line 25)
A(c,:) = [currPartID mean(part(:,8)) std(part(:,8)) mean(part(:,11)) std(part(:,11))];
Turlough Hughes
Turlough Hughes am 16 Mai 2020
I made a mistake. It should work fine now.

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