minimum of a 3D matrix
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M=rand(2,2,3)
[minM idx] = min(M(:));
[n m t] = ind2sub(size(M),idx)
minM
M(n,m,t)
I know this will give the minimum of the M matrix.
However, I want minimum value only for each M(:,:,i) part.
Is there anyway to do that?
Thanks in advance!
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Azzi Abdelmalek
am 31 Okt. 2012
Bearbeitet: Azzi Abdelmalek
am 31 Okt. 2012
M=rand(2,2,3);
out=min(reshape(min(M),size(M,2),[],1))'
or
out=arrayfun(@(x) min(min(M(:,:,x))),1:size(M,3))'
If you want to get the corresponding index
M=rand(6,4,5);
[n,m,p]=size(M)
[c,idx]=min(M)
[c1,idx2]=min(c)
idx1=arrayfun(@(x) idx(1,idx2(1,1,x),x),(1:p)')
v=[c1(:) idx1(:) idx2(:) (1:p)' ]
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Weitere Antworten (1)
Image Analyst
am 31 Okt. 2012
Try this:
minOfPlane = min(min(M(:,:, t)))
9 Kommentare
Andrei Bobrov
am 31 Okt. 2012
[v, i1] = min(reshape(M,[],size(M,3)));
min_idx_m_n_t = [rem(i1-1,size(M,1))+1; ceil(i1/size(M,1)); 1:size(M,3)]';
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