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Help with return to nested loop

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Maya Harel
Maya Harel am 6 Mai 2020
Kommentiert: Image Analyst am 8 Mai 2020
Hi, I need help with loops,
I have a while loop and in it I need to check input so I used nestef if
if the input is not valid it will print a msg and what I cannot seem to do is to send it beck to the beginning of the while loop to insert a different input
But whenever I try to print break or return at the end of the if, it just ends the whole function and not returns to the beggining of the loop
  2 Kommentare
KSSV
KSSV am 6 Mai 2020
Show us the whole code ..
Maya Harel
Maya Harel am 6 Mai 2020
function spellMat = SpellStoring()
%the function will recive spells, check their validity and if they are
%valid, and if so it will add them to a metrix
i = 0;
x = 1;
while x==1 %will continue forever until an inside break
i = i+1; %row number
spell = input("Please enter a spell. to stop enter the word 'stop'",'s');
grade = str2double(spell(5:7)); %transfer the 5-7 varieble to one grade
if strcmp(spell,'stop') %check if writen stop
return
else %if not, continue to check validity
if isempty(intersect('HP RW HG',spell(1:2)))... %compare name to valid ones
|| isempty(intersect('ABCDEFG',spell(3)))... %compare grade to valid ones
|| isempty(intersect('IAC',spell(4)))... %compare spell to valid ones
|| grade <=100 && grade<= 000 || isempty(intersect('WSCN',spell(8)))
%check grade and tresure validity
disp('Invalid spell representation');
return
end
end
spellMat = zeros(i,8);
spellMat = [spell; spellMat];
end
end

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Julian Schmid
Julian Schmid am 6 Mai 2020
Bearbeitet: Julian Schmid am 6 Mai 2020
From what I got you want to do something like that? It is easier to get an idea, if you provide the code you have written so far. The break or return statement does not end the if statement but the loop you are currently in.
inputArray = logical([1 0 1 0 0]); % can be strings and other numbers
nInput = length(inputArray);
ii = 1; % initialize index counter
while ii ~= nInput % nInput = number of arguments you want to check
if inputArray(ii) == false % or strcmp(inputArray(ii),'some condition') or ...
% input is wrong, display a message
disp('Something went wrong')
end
% increase counter
ii = ii + 1;
end
  9 Kommentare
Maya Harel
Maya Harel am 6 Mai 2020
Bearbeitet: Image Analyst am 8 Mai 2020
Thank you so much. It works!
Image Analyst
Image Analyst am 8 Mai 2020
Maya can you then "Accept this answer" to give Julian credit (reputation points) for helping you? And also to let others know it's solved and ou've moved on. Thanks in advance.

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