Deleting Rows inbetween NaN values.
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I got a row vector that looks like this: V = [ 1 4 5 NaN 0 9 3 1 3 NaN 1 5 3 0 7 NaN 7 4 2 1 NaN 9 4 ]. I want to delete all the columns in between the NaN values, and place the remaining columns in a cell array, it will look like this: Output = { [ 1 4 5 ] [ 1 5 3 0 7 ] [ 9 4 ] }. Not all the vectors in the array will be the same length, so a simple reshape will not work. There are thousands of lines as well. Thank You.
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Peng Li
am 14 Apr. 2020
It wasn't quite clear that the [1 5 3 0 7] subset is also in between two NaN values, while you keep it?
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Vinai Datta Thatiparthi
am 23 Apr. 2020
Hi Chad,
Understanding the problem from the single example that you mentioned, this following approach was one of the simplest that I could think of -
v = [ 1 4 5 NaN 0 9 3 1 3 NaN 1 5 3 0 7 NaN 7 4 2 1 NaN 9 4 ]; % Input array
idN = isnan(v); % For NaNs in array
idF = find(idN == 1); % Find indices of NaNs
out = {}; % Output cell array
for i = 1:2:numel(idF)
if i == 1
out{end+1} = v(1:idF(1)-1); % For first index
else
out{end+1} = v(idF(i-1)+1:idF(i)-1); % For the rest
end
end
if rem(numel(idF),2) == 0
out{end+1} = v(idF(end)+1:end); % At the end
end
Hope this helps!
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