Forming loop to perform same action
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I am having problem creating the loop for the task.
Thres = 0.17;
istrue1= ((x>=928 & x<=1139) & y>=Thres)|((x>=2527 & x<=2856) & y>=Thres)|((x>=4113 & x<=4376) & y>=Thres)|((x>=5464 & x<=5643) & y>=Thres)|((x>=7254 & x<=7604) & y>=Thres);
TP = sum(istrue1);
Using the command I can find out the value of TP for a particular value of thres. But I want to vary the value of thres from 0:0.1:1 and want to get 10 values of TP simultaneously rather than changing Thres each time. I know it is easy but not for me. Please help.
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dpb
am 4 Apr. 2020
Thres = 0.17;
istrue1=((x>= 928 & x<=1139) & y>=Thres) | ...
((x>=2527 & x<=2856) & y>=Thres) | ...
((x>=4113 & x<=4376) & y>=Thres) | ...
((x>=5464 & x<=5643) & y>=Thres) | ...
((x>=7254 & x<=7604) & y>=Thres);
is same as
istrue1=(x>= 928 & x<=1139 | ...
x>=2527 & x<=2856 | ...
x>=4113 & x<=4376 | ...
x>=5464 & x<=5643 | ...
x>=7254 & x<=7604) & y>=Thres);
Is place for my "syntactic sugar" helper utility iswithin...
istrue1=(iswithin(x, 928,1139) | ...
iswithin(x,2527,2856) | ...
iswithin(x,4113,4376) | ...
iswithin(x,5464,5643) | ...
iswithin(x,7254,7604)) & y>=Thres);
to reduce the clutter of all the tests conditions by moving into the function.
function flg=iswithin(x,lo,hi)
% returns T for values within range of input
% SYNTAX:
% [log] = iswithin(x,lo,hi)
% returns T for x between lo and hi values, inclusive
flg= (x>=lo) & (x<=hi);
end
2 Kommentare
dpb
am 5 Apr. 2020
As shown, it doesn't replace the individual tests, just hides the clutter.
I don't see any brilliant vectorizing available here; could build a function that looped over an array of lo, hi intervals or write the loop construct at this level would probably be my choice if there are variable numbers of regions and do this much. It's a situation haven't run into in my own code so hadn't attacked it, specifically.
Weitere Antworten (1)
Image Analyst
am 4 Apr. 2020
Bearbeitet: Image Analyst
am 4 Apr. 2020
Rather than be so complicated, break it into parts, like
term1 = (x>=928 & x<=1139)
term2 = y>=Thres
term3 = (x>=2527 & x<=2856)
and so on. Then look at the size and values of each term. This is just basic debugging... Then
put Thresh into a loop
Thres = [0 : 0.1 : 1];
for k = 1 : length(Thres)
thisThres = Thres(k);
istrue1 = ...... function thisThresh instead of Thres
end
4 Kommentare
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