Need help with sorting a string when a numeric vector moves also . Can't use the sort or min function

So im trying to sort a string basec on how to Times variable moves in Task 2, i figured out how to sort the Times in ascending order but i want the Names variable to move concurrent with where the Times numbers go can anyone help?

%Task 1
load('Processes_4.mat');
[ROW,COL] = size(Names);
[r,c]= size(Times);
str1 = isvector(Names);
str=isstring(Names);
vect= isnumeric(Times);
vect1 =isvector(Times);
if vect~=1 || vect1 ~=1 || r ==1 && c ==1 
    Times_ =1;
else 
    Times_ =0;
end
if str1 ~=1 || str ~=1 || ROW ==1 && COL ==1 
    names_ =1;
else 
    names_ =0;
end
if  Times_ == 1 && names_ ==1
    error('Both provided variables is invalid')
end
if str~=1 || vect1 ~=1 || r==1 && c==1
    error('Times variabble is invalid')
end
if str~= 1 || str~=1 || ROW ~=1 && COL ~=1
    error('Names variable is invalid');
end

%Task 2 
T= length(Times);
N=length(Names);
for i = 1:T
  for j= 1:T
    if Times(j) > Times(i)
      Newtime=Times(j);
      Times(j) = Times(i);
      Times(i) =Newtime;
      if Names(Times(j)) > Names(Times(i))
        Newname= Names(Times(j));
        Names(Times(j)) = Names(Times(i));
        Names(Times(i)) =Newname;
      end
    end
  end
end

Answer 1

[Ameer Hamza]

I cannot run your code with the mat file, so it is unclear what you are trying to do. But if you want to sort a string array, in the same order as a numeric array then try something like this

str = ["dog", "fox", "Quick", "brown", "jumps", "over",  "lazy", ];
num = [7 3 1 2 4 5 6];
A = [num' (1:numel(num))'];
A(num,:) = A;
str = str(A(:,2));

[Image Analyst]

Why can't you use the min() or sort() function?????

[Alex Doan]

It's a condition for our task

[Ameer Hamza]

Ah! I missed that you don't want to use sort() function. Check the updated answer.

[Ameer Hamza]

Note that this will only work if the numeric vectors have all numbers from 1 to n.