how to split a string

i need to create a function named breakline which inputs a string (char, 1 × N) and a linewidth (integer, scalar). The function then splits the string into smaller strings which are smaller than the linewidth.

The output to the function is an array which contains all of the split up lines (cell array, 1 × M).

for example

out=breakupLine(’123456789’,4) 
out = 
{ 
[1,1] = ’1234’ 
[1,2] = ’5678’
 [1,3] = ’9’
 }

[Walter Roberson]

It is not possible to get the output in exactly that format. The initial part showing the index can only appear if you create the output as all one character vector, contradicting the requirement that it be a cell array.

Answer 1

[Walter Roberson]

If the current vector is shorter than N or exactly N then add the complete current vector to the end of the cell array and return. Otherwise index the first N characters from the current vector and add them to the end of the cell array, and remove N characters from the beginning of the current vector overwriting the current vector and loop back.

[Mitchie Teotico]

could you show an example

[Walter Roberson]

ThisRow = RemainingLetters(1:4);
RemainingLetters = RemainingLetters(5:end);

Answer 2

[Nik Niki]

test_data_name="kjashfk, kjasdklasdfas, 3";
test_data_name = split(test_data_name)

test_data_name = 3×1 string array
    "kjashfk,"
    "kjasdklasdfas,"
    "3"

Answer 3

[Image Analyst]

Here is one way:

out=breakupLine('123456789', 4) 

out = 1×3 cell array
    {'1234'}    {'5678'}    {'9'}

%=====================================================
function out=breakupLine(str, substringLength) 
stringLength = length(str);
loopCounter = 1;
for k = 1 : substringLength : stringLength
    index1 = k;
    index2 = min(k + substringLength - 1, stringLength);
    out{loopCounter} = str(index1 : index2);
    loopCounter = loopCounter + 1;
end
end

Answer 4

[DGM]

To address the OP's particular request:

linew = 4;
teststr = '123456789';

excess = rem(numel(teststr),linew);
output = reshape(teststr(1:end-excess),linew,[]).';
output = [num2cell(output,2); teststr(end-excess+1:end)]

output = 3×1 cell array
    {'1234'}
    {'5678'}
    {'9'   }

I don't know that this is particularly efficient, but it works. It may have advantages at some scale, but I haven't tested that.