while loop ends too early
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Ann Gerber
am 21 Mär. 2020
Kommentiert: Ann Gerber
am 22 Mär. 2020
Hi everyone,
Why is this loop not executed for t_max = 5.0000e-04 anymore? if I output t, the maximum (last) value is 5.0000e-04 instead of 5.0100e-04
delta_t = 10e-7;
t_max = 5.0000e-04; %[s]
t = 0;
while t <= t_max
t = t+delta_t;
end
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Akzeptierte Antwort
Ameer Hamza
am 21 Mär. 2020
Bearbeitet: Ameer Hamza
am 21 Mär. 2020
Image Analyst and Sriram explained the reason as it is caused by the finite precision of floating-point representation. One way is to solve the issue with limited precision is to use variable precision arithmetic
delta_t = vpa(10e-7);
t_max = vpa(5.0000e-04); %[s]
t = vpa(0);
while t <= t_max
t = t+delta_t;
end
However, note that this will be slower as compared to the numeric version. The other solution is to add a tolerance value for comparison
delta_t = 10e-7;
t_max = 5.0000e-04; %[s]
t = 0;
while t <= t_max + 1e-10 % small tolerance in comparison
t = t+delta_t;
end
Weitere Antworten (2)
Image Analyst
am 21 Mär. 2020
Take the semicolon off and format long and you'll see why
format long g;
format compact
delta_t = 10e-7;
t_max = 5.0000e-04; %[s]
t = 0;
while t <= t_max
t = t+delta_t
end
t =
0.000498000000000006
t =
0.000499000000000006
t =
0.000500000000000006
You see, it ends up being slightly larger than 0.0005 so it doesn't even enter the loop that last time.
So, basically you need to see the FAQ for an explanation of digitization error: FAQ Why_is_0.3_-_0.2_-_0.1_.28or_similar.29_not_equal_to_zero?
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Sriram Tadavarty
am 21 Mär. 2020
Hi Ann,
The loop runs as expected, since the floating values are represented in IEEE 754 format as described here.
To know what the value of t that end from the loop, use format long as below:
format long
>> t_max
t_max =
5.000000000000000e-04
>> t
t =
5.000000000000056e-04
Observe that t is lager than t_max and thus, the loop ended.
Hope this helps.
Regards,
Sriram
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