Numeric matrix to string matrix

Hi,

Newbie here, need some assistance in solving this problem.

Input is a numeric matrix x (any dimension). Return value is a string matrix.

The rules are :

If the x <= 30, then return “small”, if 30 < x <= 50, then return “medium”, otherwise return “high”

When I run the first "If" statement by itself I get x = "low" "low" "low" "low"

Then when I add the elseif statement I get nothing. Matlab simply ouputs the same results.

It seems like the code is only looking at the first row of my matrix. It also seems that it's considering 45 as less than 30.

I appreciate all the help in advance. I'm new learner, slowly learning programming.

First if statement only.

A = [1 2 45 4 ; 5 6 45 8];

 for i = 1:length(A);
    if A(i) <= 30 
        x(i)= "low"
    end
 end
 
 >> 
 x = 

  1×4 string array

    "low"    "low"    "low"    "low"

elseif statement

    A = [1 2 45 4 ; 5 6 45 8];

 for i = 1:length(A);
    if A(i) <= 30 
        x(i)= "low"
    elseif 30 > A(i) & A(i)<= 50
        x(i) = "medium"
    end
 end
 
 >> 
 x = 

  1×4 string array

    "low"    "low"    "low"    "low"

Answer 1

[Ameer Hamza]

x = [5 15 25;
    35 45 55;
    65 75 85];
 
result = strings(size(x));
result(x<=30) = "small";
result(x>30 & x<=50) = "medium";
result(x>50) = "large";

The result is

result = 

  3×3 string array

    "small"     "small"     "small"
    "medium"    "medium"    "large"
    "large"     "large"     "large"

[Emmanuel Matata Bili Bili]

Hi - Ameer,

Thank you for your answer. I completely forgot to say thanks.

I appreciate the help. Thanks!!!!

Answer 2

[Guillaume]

The easiest way, by far, to do this in matlab is:

A = [1 2 45 4 ; 5 6 45 8]; %demo data

result = discretize(A, [-Inf, 30, 50, Inf], ["low", "medium", "high"])

[Emmanuel Matata Bili Bili]

Allo Guillaume,

Thanks for the answer!

I completely got sidetracked and excited about trying both solutions and I forgot to say thanks.

It all worked fine with your solution as well.

Thank you!!