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reshape a char array

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Laura
Laura am 26 Feb. 2020
Kommentiert: Guillaume am 26 Feb. 2020
Hi,
I have the following MWE and I don't understand what matlab is producing:
I start with a simple 21-length char array:
ex = 'caggtgcagctggtgcagtct'
that I would like to reshape into a 7-by-3 array. Of course, I could use a loop for this, but I thought that I could just reshape it. However, when I do
reshape(ex, [7,3])
ans =
7×3 char array
'cag'
'agc'
'gca'
'gtg'
'tgt'
'ggc'
'ctt'
This makes no sense to me. I was expecting
'cag'
'gtg'
'cag'
'ctg'
'gtg'
'cag'
'tct'
I also tried reshape(ex, 7,3) and reshape(ex(:), 7, 3) without any luck. What is matlab doing? TIA
  1 Kommentar
Guillaume
Guillaume am 26 Feb. 2020
Matlab is column major. This means that when you reshape something into something else, the something else is filled column by column, not row by row. So, indeed as David shows, to get the output you want you reshape then transpose.

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Akzeptierte Antwort

David Hill
David Hill am 26 Feb. 2020
reshape(ex,[3,7])';
First number is row and second is column. Matrix is numbered down first.
  2 Kommentare
Laura
Laura am 26 Feb. 2020
Bearbeitet: Laura am 26 Feb. 2020
wow, that is really counter-intuitive. I guess I am used to other programming languages (i.e. python) that do not "number down first"...
Thank you!
Guillaume
Guillaume am 26 Feb. 2020
You'll find a number of languages (C-based mostly) are row majors and an equivalent number are column-major (Matlab, Fortran, and other math-focused languages) while a few can't make their mind up (eg. OpenGL).
So, it's only counterintuitive if you've never been exposed to the other side.

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